x^2+1.2x-0.66=0

Solution for x^2+1.2x-0.66=0 equation:

x^2+1.2x-0.66=0

a = 1; b = 1.2; c = -0.66;
Δ = b2-4ac
Δ = 1.22-4·1·(-0.66)
Δ = 4.08
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.2)-\sqrt{4.08}}{2*1}=\frac{-1.2-\sqrt{4.08}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.2)+\sqrt{4.08}}{2*1}=\frac{-1.2+\sqrt{4.08}}{2}
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